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2x^2+17x-69=0
a = 2; b = 17; c = -69;
Δ = b2-4ac
Δ = 172-4·2·(-69)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-29}{2*2}=\frac{-46}{4} =-11+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+29}{2*2}=\frac{12}{4} =3 $
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